16x^2-136x+225=0

Solution for 16x^2-136x+225=0 equation:

16x^2-136x+225=0

a = 16; b = -136; c = +225;
Δ = b2-4ac
Δ = -1362-4·16·225
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-136)-64}{2*16}=\frac{72}{32}
=2+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-136)+64}{2*16}=\frac{200}{32}
=6+1/4
$